\n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"Head wind 10 crosswind 12 kt","comment":{"@type":"Comment","text":"Head wind 10 crosswind 12 kt"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"Head wind 15 kt crosswind 15 kt","comment":{"@type":"Comment","text":"Head wind 15 kt crosswind 15 kt"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"Head wind 20 kt crosswind 20 kt","comment":{"@type":"Comment","text":"Head wind 20 kt crosswind 20 kt"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"Head wind 19 kt crosswind 23 kt","comment":{"@type":"Comment","text":"Head wind 19 kt crosswind 23 kt"}}],"acceptedAnswer":[{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"Head wind 19 kt crosswind 23 kt","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"General","text":"Departing SID requires 6.1% gradient with T/O flaps, speed 130 kts to 1800ft and thereafter a 5% gradient to FL80 clean at 230 kts. What is the ROC required to 1800ft?","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"600 fpm to 1800 ft with non-standard speed change altitude.","comment":{"@type":"Comment","text":"600 fpm to 1800 ft with non-standard speed change altitude."}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"1150 fpm with standard speed change altitude","comment":{"@type":"Comment","text":"1150 fpm with standard speed change altitude"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"800 fpm to 1800 ft with non-standard speed change altitude.","comment":{"@type":"Comment","text":"800 fpm to 1800 ft with non-standard speed change altitude."}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"1250 fpm with standard speed change altitude.","comment":{"@type":"Comment","text":"1250 fpm with standard speed change altitude."}}],"acceptedAnswer":[{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"800 fpm to 1800 ft with non-standard speed change altitude.","comment":{"@type":"Comment","text":"The Rate of Climb (ROC) required to climb to 1800ft is 800 fpm with a non-standard speed change altitude when departing on the Standard Instrument Departure (SID) that requires a 6.1% gradient with takeoff flaps and a speed of 130 kts."},"answerExplanation":{"@type":"Comment","text":"The Rate of Climb (ROC) required to climb to 1800ft is 800 fpm with a non-standard speed change altitude when departing on the Standard Instrument Departure (SID) that requires a 6.1% gradient with takeoff flaps and a speed of 130 kts."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Performance Class A - Use Of Data","text":"Refer to the annex or CAP 698 Figure 4.5. Given the following information what is the Climb Limited Take-Off Mass?OAT + 35°CPressure altitude 2000 ftFlaps 5°A/C packs OFFAnti-icing OFFPMC OFF \n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"52800 kg","comment":{"@type":"Comment","text":"52800 kg"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"53700 kg","comment":{"@type":"Comment","text":"53700 kg"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"57900 kg","comment":{"@type":"Comment","text":"57900 kg"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"57000 kg","comment":{"@type":"Comment","text":"57000 kg"}}],"acceptedAnswer":[{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"57900 kg","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Performance Class A - Theory","text":"With regard to the FMC and reduced thrust take-off’s which of the following statements is correct.","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"Reduced thrust cannot be used on a contaminated runway.","comment":{"@type":"Comment","text":"Reduced thrust cannot be used on a contaminated runway."}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"Reduced thrust is not recommended at very low temperatures (OAT).","comment":{"@type":"Comment","text":"Reduced thrust is not recommended at very low temperatures (OAT)."}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"Reduced thrust can lower VMCG and VMCA","comment":{"@type":"Comment","text":"Reduced thrust can lower VMCG and VMCA"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"Reduced thrust cannot be used on a wet runway","comment":{"@type":"Comment","text":"Reduced thrust cannot be used on a wet runway"}}],"acceptedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"Reduced thrust cannot be used on a contaminated runway.","comment":{"@type":"Comment","text":"Reduced thrust take-off cannot be used on a contaminated runway."},"answerExplanation":{"@type":"Comment","text":"Reduced thrust take-off cannot be used on a contaminated runway."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Performance Class B - Use Of Data","text":"Please refer to the annex or to CAP 698, Figure 3.7. What is the time required by a multi-engined piston aeroplane to climb 2400 ft? Assume that the rate of climb is constant throughout the climb and equals the rate of climb at 6000 ft pressure altitude. Use the following data:2 engines operating at maximum continuous power,Gear retracted,Pressure altitude: 6000 ft,OAT: +17° C,Mass: 4000 lb. \n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"8 minutes 0 seconds","comment":{"@type":"Comment","text":"8 minutes 0 seconds"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"3 minutes 55 seconds","comment":{"@type":"Comment","text":"3 minutes 55 seconds"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"1 minute 33 seconds","comment":{"@type":"Comment","text":"1 minute 33 seconds"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"1 minute 55 seconds","comment":{"@type":"Comment","text":"1 minute 55 seconds"}}],"acceptedAnswer":[{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"1 minute 33 seconds","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Performance Class B - Theory","text":"A single engine aircraft has a gross glide gradient of 8%. Determine the net glide distance from 10 000 ft to 2 000 ft:","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"15.5 NM","comment":{"@type":"Comment","text":"15.5 NM"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"16.5 NM","comment":{"@type":"Comment","text":"16.5 NM"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"17 NM","comment":{"@type":"Comment","text":"17 NM"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"94 120 NM","comment":{"@type":"Comment","text":"94 120 NM"}}],"acceptedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"15.5 NM","comment":{"@type":"Comment","text":"The net glide distance can be calculated by multiplying the gross glide gradient (8%) by the difference in altitude (8000 ft), and then dividing by 100 to convert it to nautical miles. Therefore, the net glide distance from 10 000 ft to 2 000 ft is 15.5 NM."},"answerExplanation":{"@type":"Comment","text":"The net glide distance can be calculated by multiplying the gross glide gradient (8%) by the difference in altitude (8000 ft), and then dividing by 100 to convert it to nautical miles. Therefore, the net glide distance from 10 000 ft to 2 000 ft is 15.5 NM."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"General","text":"Under which conditions would VMC be lowest?","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"Low temperatures, low pressure altitudes, low humidity.","comment":{"@type":"Comment","text":"Low temperatures, low pressure altitudes, low humidity."}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"Low temperatures, high pressure altitudes, low humidity.","comment":{"@type":"Comment","text":"Low temperatures, high pressure altitudes, low humidity."}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"High temperatures, high pressure altitudes, high humidity.","comment":{"@type":"Comment","text":"High temperatures, high pressure altitudes, high humidity."}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"High temperatures, low pressure altitudes, high humidity.","comment":{"@type":"Comment","text":"High temperatures, low pressure altitudes, high humidity."}}],"acceptedAnswer":[{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"High temperatures, high pressure altitudes, high humidity.","comment":{"@type":"Comment","text":"VMC (Minimum Control Speed) would be lowest under conditions of high temperatures, high pressure altitudes, and high humidity."},"answerExplanation":{"@type":"Comment","text":"VMC (Minimum Control Speed) would be lowest under conditions of high temperatures, high pressure altitudes, and high humidity."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Performance Class A - Use Of Data","text":"Refer to figure 032-62.Given: Airport elevation:\n \n1 998 ft\nTemperature (OAT):\n+38 ⁰C\nTailwind:\n8 kt\nTyres:\n \n225 mph\nFlaps:\n5⁰\nAircraft:\nmedium range jet\nPower management computer (PMC):\nON\nDetermine the tyre speed limited take-off mass for a departure from Madrid, Spain:\n\n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"79 100 kg","comment":{"@type":"Comment","text":"79 100 kg"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"78 850 kg","comment":{"@type":"Comment","text":"78 850 kg"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"84 300 kg","comment":{"@type":"Comment","text":"84 300 kg"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"73 900 kg","comment":{"@type":"Comment","text":"73 900 kg"}}],"acceptedAnswer":[{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"73 900 kg","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Performance Class A - Theory","text":"What is the effect of an inoperative anti-skid system on aeroplane performance?","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"The Regulated Take-Off Mass (RTOM) is only affected on a wet runway.","comment":{"@type":"Comment","text":"The Regulated Take-Off Mass (RTOM) is only affected on a wet runway."}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"The performance remains unaffected when using an auto-brake system and thrust reversers.","comment":{"@type":"Comment","text":"The performance remains unaffected when using an auto-brake system and thrust reversers."}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"It increases the landing distance required due to a reduced braking capability.","comment":{"@type":"Comment","text":"It increases the landing distance required due to a reduced braking capability."}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"V1 remains the same, but the Regulated Take-Off Mass (RTOM) decreases.","comment":{"@type":"Comment","text":"V1 remains the same, but the Regulated Take-Off Mass (RTOM) decreases."}}],"acceptedAnswer":[{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"It increases the landing distance required due to a reduced braking capability.","comment":{"@type":"Comment","text":"An inoperative anti-skid system on an aeroplane increases the landing distance required as it results in reduced braking capability."},"answerExplanation":{"@type":"Comment","text":"An inoperative anti-skid system on an aeroplane increases the landing distance required as it results in reduced braking capability."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Performance Class B - Use Of Data","text":"Refer to figure or CAP697 file 2.1. Given the following information, what is the required fuel to climb?\nAirport Pressure Altitude: 4000 ft\nAirport OAT: +10°C\nClimb to: FL100\nOAT at FL100: -5°C T\nTake-Off Mass: 3400 lb\nGear: up\n\n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"4.2 gal","comment":{"@type":"Comment","text":"4.2 gal"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"16 gal","comment":{"@type":"Comment","text":"16 gal"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"8.0 gal","comment":{"@type":"Comment","text":"8.0 gal"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"2.8 gal","comment":{"@type":"Comment","text":"2.8 gal"}}],"acceptedAnswer":[{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"2.8 gal","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]}]},{"@context":"https://schema.org/","@type":"AggregateRating","itemReviewed":{"@type":"Course","name":"IT Quiz ATPL (A) Performance","description":"Quiz ATPL (A) Performance - Quiz: 971 domande con spiegazioni e soluzioni, disponibili anche in PDF","provider":{"@type":"Organization","name":"Easy Quizzz","sameAs":"https://www.easy-quizzz.com"},"offers":[{"@type":"Offer","category":"Licenza di Pilota di Linea ATPL Aereo","priceCurrency":"EUR","price":0}],"about":["Performance Class A - Use Of Data","Performance Class A - Theory","General","Performance Class B - Theory","Performance Class B - Use Of Data"],"hasCourseInstance":[{"@type":"CourseInstance","courseMode":"Online","courseWorkload":"PT20M"}]},"ratingCount":248,"ratingValue":4.9,"bestRating":5,"worstRating":0}]}
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Quiz
Domanda 1/101/10
Performance Class B - Theory
Performance Class B - Theory
Performance Class B - Theory
Refer to figure or CAP698 file 4.1.
Calculate the relative direction of the wind to the runway. i.e. (wind direction - runway direction) or (runway direction - wind direction).
Example: W/V 330/30
Runway 0
Wind angle = 50°
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
Head wind 10 crosswind 12 kt
B.
Head wind 15 kt crosswind 15 kt
C.
Head wind 20 kt crosswind 20 kt
D.
Head wind 19 kt crosswind 23 kt
.
Risposta Corretta: D
Quiz
Domanda 2/102/10
General
General
General
Departing SID requires 6.1% gradient with T/O flaps, speed 130 kts to 1800ft and thereafter a 5% gradient to FL80 clean at 230 kts. What is the ROC required to 1800ft?
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
600 fpm to 1800 ft with non-standard speed change altitude.
B.
1150 fpm with standard speed change altitude
C.
800 fpm to 1800 ft with non-standard speed change altitude.
D.
1250 fpm with standard speed change altitude.
The Rate of Climb (ROC) required to climb to 1800ft is 800 fpm with a non-standard speed change altitude when departing on the Standard Instrument Departure (SID) that requires a 6.1% gradient with takeoff flaps and a speed of 130 kts.
Risposta Corretta: C
Quiz
Domanda 3/103/10
Performance Class A - Use Of Data
Performance Class A - Use Of Data
Performance Class A - Use Of Data
Refer to the annex or CAP 698 Figure 4.5. Given the following information what is the Climb Limited Take-Off Mass?OAT + 35°CPressure altitude 2000 ftFlaps 5°A/C packs OFFAnti-icing OFFPMC OFF
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
52800 kg
B.
53700 kg
C.
57900 kg
D.
57000 kg
.
Risposta Corretta: C
Quiz
Domanda 4/104/10
Performance Class A - Theory
Performance Class A - Theory
Performance Class A - Theory
With regard to the FMC and reduced thrust take-off’s which of the following statements is correct.
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
Reduced thrust cannot be used on a contaminated
runway.
B.
Reduced thrust is not recommended at very low
temperatures (OAT).
C.
Reduced thrust can lower VMCG and VMCA
D.
Reduced thrust cannot be used on a wet runway
Reduced thrust take-off cannot be used on a contaminated runway.
Risposta Corretta: A
Quiz
Domanda 5/105/10
Performance Class B - Use Of Data
Performance Class B - Use Of Data
Performance Class B - Use Of Data
Please refer to the annex or to CAP 698, Figure 3.7. What is the time required by a multi-engined piston aeroplane to climb 2400 ft? Assume that the rate of climb is constant throughout the climb and equals the rate of climb at 6000 ft pressure altitude. Use the following data:2 engines operating at maximum continuous power,Gear retracted,Pressure altitude: 6000 ft,OAT: +17° C,Mass: 4000 lb.
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
8 minutes 0 seconds
B.
3 minutes 55 seconds
C.
1 minute 33 seconds
D.
1 minute 55 seconds
.
Risposta Corretta: C
Quiz
Domanda 6/106/10
Performance Class B - Theory
Performance Class B - Theory
Performance Class B - Theory
A single engine aircraft has a gross glide gradient of 8%. Determine the net glide distance from 10 000 ft to 2 000 ft:
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
15.5 NM
B.
16.5 NM
C.
17 NM
D.
94 120 NM
The net glide distance can be calculated by multiplying the gross glide gradient (8%) by the difference in altitude (8000 ft), and then dividing by 100 to convert it to nautical miles. Therefore, the net glide distance from 10 000 ft to 2 000 ft is 15.5 NM.
Low temperatures, high pressure altitudes, low humidity.
C.
High temperatures, high pressure altitudes, high humidity.
D.
High temperatures, low pressure altitudes, high humidity.
VMC (Minimum Control Speed) would be lowest under conditions of high temperatures, high pressure altitudes, and high humidity.
Risposta Corretta: C
Quiz
Domanda 8/108/10
Performance Class A - Use Of Data
Performance Class A - Use Of Data
Performance Class A - Use Of Data
Refer to figure 032-62.Given:
Airport elevation:
1 998 ft
Temperature (OAT):
+38 ⁰C
Tailwind:
8 kt
Tyres:
225 mph
Flaps:
5⁰
Aircraft:
medium range jet
Power management computer (PMC):
ON
Determine the tyre speed limited take-off mass for a departure from Madrid, Spain:
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
79 100 kg
B.
78 850 kg
C.
84 300 kg
D.
73 900 kg
.
Risposta Corretta: D
Quiz
Domanda 9/109/10
Performance Class A - Theory
Performance Class A - Theory
Performance Class A - Theory
What is the effect of an inoperative anti-skid system on aeroplane performance?
Seleziona la risposta:Seleziona la risposta
1 risposta corretta
A.
The Regulated Take-Off Mass (RTOM) is only affected on a wet runway.
B.
The performance remains unaffected when using an auto-brake system and thrust reversers.
C.
It increases the landing distance required due to a reduced braking capability.
D.
V1 remains the same, but the Regulated Take-Off Mass (RTOM) decreases.
An inoperative anti-skid system on an aeroplane increases the landing distance required as it results in reduced braking capability.
Risposta Corretta: C
Quiz
Domanda 10/1010/10
Performance Class B - Use Of Data
Performance Class B - Use Of Data
Performance Class B - Use Of Data
Refer to figure or CAP697 file 2.1.
Given the following information, what is the required fuel to climb?
Airport Pressure Altitude: 4000 ft
Airport OAT: +10°C
Climb to: FL100
OAT at FL100: -5°C T
Take-Off Mass: 3400 lb
Gear: up
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Info quiz:
Nome del quiz:Quiz ATPL (A) Performance
Numero totale di domande:971
Numero di domande per il test:100
Punteggio di superamento:70%
Numero di argomenti:5 argomenti
Argomenti di studio:Numero di domande:
General:450 domande
Performance Class A - Theory:245 domande
Performance Class A - Use Of Data:80 domande
Performance Class B - Theory:128 domande
Performance Class B - Use Of Data:68 domande
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