\n$1","comment":{"@type":"Comment","text":"282º \n$1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"296º \n$1","comment":{"@type":"Comment","text":"296º \n$1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"301º \n$1","comment":{"@type":"Comment","text":"301º \n$1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"284º \n$1","comment":{"@type":"Comment","text":"284º \n$1"}}],"acceptedAnswer":[{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"296º \n$1","comment":{"@type":"Comment","text":"To calculate the actual true track, you need to add the planned true track of 283º with the actual drift angle of 7ºR (right) as the drift is towards the right. Therefore, 283º + 7º = 290º. Then, adjust for the easterly variation of 12ºE by subtracting it from the result. So, 290º - 12º = 278º. However, since the variation is east, you need to add it instead. Therefore, 278º + 12º = 290º. Hence, the actual true track is 290º."},"answerExplanation":{"@type":"Comment","text":"To calculate the actual true track, you need to add the planned true track of 283º with the actual drift angle of 7ºR (right) as the drift is towards the right. Therefore, 283º + 7º = 290º. Then, adjust for the easterly variation of 12ºE by subtracting it from the result. So, 290º - 12º = 278º. However, since the variation is east, you need to add it instead. Therefore, 278º + 12º = 290º. Hence, the actual true track is 290º."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Time","text":"On the 15th October, a pilot is departing from Auckland, New Zealand (37°00'S, 174°47'E,position west of the International Date Line; LT = UTC + 12 hours) for a flight to Honolulu inHawaii, U.S. (21°19'N, 157°55'W, position east of the International Date Line; LT = UTC - 10hours).When departing, the aircraft's master clock displays 08:15 UTC.After landing, the pilot records a flight time of 8 hours and 37 minutes.Which of the below statements is correct?","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"The aircraft arrives in Honolulu at 16:52 LT on the 15th October. $1","comment":{"@type":"Comment","text":"The aircraft arrives in Honolulu at 16:52 LT on the 15th October. $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"When the aircraft arrives in Honolulu, the local date in Auckland is still the 15th October. $1","comment":{"@type":"Comment","text":"When the aircraft arrives in Honolulu, the local date in Auckland is still the 15th October. $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"Upon arrival the master clock of the aircraft displays 16:52 UTC and the local date is the 16th October. $1","comment":{"@type":"Comment","text":"Upon arrival the master clock of the aircraft displays 16:52 UTC and the local date is the 16th October. $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"The aircraft arrives in Honolulu at 06:52 LT on the 15th October. $1","comment":{"@type":"Comment","text":"The aircraft arrives in Honolulu at 06:52 LT on the 15th October. $1"}}],"acceptedAnswer":[{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"The aircraft arrives in Honolulu at 06:52 LT on the 15th October. $1","comment":{"@type":"Comment","text":"The aircraft arrives in Honolulu at 06:52 LT on the 15th October."},"answerExplanation":{"@type":"Comment","text":"The aircraft arrives in Honolulu at 06:52 LT on the 15th October."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Visual Flight Rule (VFR) Navigation","text":"(See Image). A pilot has planned a flight from aerodrome Strunkovice (LKSR) (N49°05', E014°04') to aerodrome Hohenfels (ETIH) (N49°13', E011°50') using the route shown on the annex. The pilot has been looking out while the aircraft has been drifting to the right of track. NOT looking at the stop watch, he/she mistakes EDNF (N48°50', E013°22') for EDMV (N48°38', E013°12') and turns right for the next leg. Seeing the mast, with elevation 3754 ft (N48°49', E013°13'), there are doubts about the aircraft's position. What is the best option to follow in order to re-establish the aircraft's position? \n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"Continue on the present heading in order to reach the next waypoint $1","comment":{"@type":"Comment","text":"Continue on the present heading in order to reach the next waypoint $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"Circle to establish the aircraft's exact position. $1","comment":{"@type":"Comment","text":"Circle to establish the aircraft's exact position. $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"Tune in the RODING (RDG) VOR/DME to confirm the aircraft's position and re-route accordingly. $1","comment":{"@type":"Comment","text":"Tune in the RODING (RDG) VOR/DME to confirm the aircraft's position and re-route accordingly. $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"Climb to a higher level, reverse track back to aerodrome Strunkovice, and re-route from there. $1","comment":{"@type":"Comment","text":"Climb to a higher level, reverse track back to aerodrome Strunkovice, and re-route from there. $1"}}],"acceptedAnswer":[{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"Tune in the RODING (RDG) VOR/DME to confirm the aircraft's position and re-route accordingly. $1","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Charts","text":"Refer to the Annex or to chart E(LO)2 from the Jeppesen GSPRM 2017. Determine the initial track from position A (N54°53', W005°18') to position B (N55°18', W003°35') and also the distance from position A to the point of crossing the meridian of W004°00'. \n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"Track: 070°(M); Distance: 48 NM $1","comment":{"@type":"Comment","text":"Track: 070°(M); Distance: 48 NM $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"Track: 067°(T); Distance: 63 NM $1","comment":{"@type":"Comment","text":"Track: 067°(T); Distance: 63 NM $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"Track: 064°(M); Distance: 48 NM $1","comment":{"@type":"Comment","text":"Track: 064°(M); Distance: 48 NM $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"Track: 070°(T); Distance: 63 NM $1","comment":{"@type":"Comment","text":"Track: 070°(T); Distance: 63 NM $1"}}],"acceptedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"Track: 070°(M); Distance: 48 NM $1","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Great Circles And Rhumb Lines","text":"Given the following information, calculate, to the nearest whole degree, the value of Earth convergence between positions A and B.A: 46°20'N, 005°40'WB: 62°40'N, 013°55'E.","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"24° $1","comment":{"@type":"Comment","text":"24° $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"11° $1","comment":{"@type":"Comment","text":"11° $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"16° $1","comment":{"@type":"Comment","text":"16° $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"8° $1","comment":{"@type":"Comment","text":"8° $1"}}],"acceptedAnswer":[{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"16° $1","comment":{"@type":"Comment","text":"Earth convergence is the angle between two meridians at a specific latitude, caused by the Earth's curvature. To calculate it, we find the difference in longitude between the two positions (13°55'E - 5°40'W = 19°35'), then multiply this by the cosine of the mean latitude (54°30'N) to get the convergence of approximately 16°."},"answerExplanation":{"@type":"Comment","text":"Earth convergence is the angle between two meridians at a specific latitude, caused by the Earth's curvature. To calculate it, we find the difference in longitude between the two positions (13°55'E - 5°40'W = 19°35'), then multiply this by the cosine of the mean latitude (54°30'N) to get the convergence of approximately 16°."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Basics of Navigation","text":"The standard parallels of a Lambert’s conical projection are 07°40’N and 38°20’N. For this chart, what is the approximate constant of the cone?","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"0.60 $1","comment":{"@type":"Comment","text":"0.60 $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"0.39 $1","comment":{"@type":"Comment","text":"0.39 $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"0.42 $1","comment":{"@type":"Comment","text":"0.42 $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"0.92 $1","comment":{"@type":"Comment","text":"0.92 $1"}}],"acceptedAnswer":[{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"0.39 $1","comment":{"@type":"Comment","text":"The constant of the cone for Lambert's conical projection can be calculated using the formula: Constant = cos(standard parallel)1 + sin(standard parallel)1 * sin(standard parallel)2\nSubstituting the given standard parallels of 07°40’N and 38°20’N, the approximate constant of the cone is 0.39."},"answerExplanation":{"@type":"Comment","text":"The constant of the cone for Lambert's conical projection can be calculated using the formula: Constant = cos(standard parallel)1 + sin(standard parallel)1 * sin(standard parallel)2\nSubstituting the given standard parallels of 07°40’N and 38°20’N, the approximate constant of the cone is 0.39."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Time","text":"While flying on an easterly track and crossing the dateline, the Local Time (LT) will (1)_____ and the date (2)_____.","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"(1) Move backward by 12 hours; (2) go back one day. $1","comment":{"@type":"Comment","text":"(1) Move backward by 12 hours; (2) go back one day. $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"(1) Stay unchanged; (2) go back one day. $1","comment":{"@type":"Comment","text":"(1) Stay unchanged; (2) go back one day. $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"(1) Stay unchanged; (2) go forward by one day. $1","comment":{"@type":"Comment","text":"(1) Stay unchanged; (2) go forward by one day. $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"(1) Move forward by 12 hours; (2) go back one day. $1","comment":{"@type":"Comment","text":"(1) Move forward by 12 hours; (2) go back one day. $1"}}],"acceptedAnswer":[{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"(1) Stay unchanged; (2) go back one day. $1","comment":{"@type":"Comment","text":"When flying on an easterly track and crossing the dateline, the Local Time (LT) will stay unchanged and the date will go back one day."},"answerExplanation":{"@type":"Comment","text":"When flying on an easterly track and crossing the dateline, the Local Time (LT) will stay unchanged and the date will go back one day."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Visual Flight Rule (VFR) Navigation","text":"On a topographical chart, contour lines that are very close together indicate that the terrain...","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"has a gradual slope. $1","comment":{"@type":"Comment","text":"has a gradual slope. $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"is a level plain. $1","comment":{"@type":"Comment","text":"is a level plain. $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"is a shallow mountain bowl. $1","comment":{"@type":"Comment","text":"is a shallow mountain bowl. $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"is steep. $1","comment":{"@type":"Comment","text":"is steep. $1"}}],"acceptedAnswer":[{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"is steep. $1","comment":{"@type":"Comment","text":"Contour lines that are very close together on a topographical chart indicate that the terrain is steep."},"answerExplanation":{"@type":"Comment","text":"Contour lines that are very close together on a topographical chart indicate that the terrain is steep."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Charts","text":"Refer to chart E(LO)2_02 from Jeppesen GSPRM 2017. Given the following bearing and range information obtained from DEN HELDER (HDR) VOR/DME (52°54´N, 004°46´E), what is the aircraft's position? (Note: Slant range corrections should be ignored)\nRadial: 258°\nRange: 63 NM\n\n ","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"52°42´N, 003°04´E $1","comment":{"@type":"Comment","text":"52°42´N, 003°04´E $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"52°46´N, 003°42´E $1","comment":{"@type":"Comment","text":"52°46´N, 003°42´E $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"53°10´N, 003°03´E $1","comment":{"@type":"Comment","text":"53°10´N, 003°03´E $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"52°46´N, 003°48´E $1","comment":{"@type":"Comment","text":"52°46´N, 003°48´E $1"}}],"acceptedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"52°42´N, 003°04´E $1","comment":{"@type":"Comment","text":"."},"answerExplanation":{"@type":"Comment","text":"."}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","name":"Great Circles And Rhumb Lines","text":"On a Direct Mercator chart, apart from meridians and the Equator, a great circle will be represented by a…","comment":{"@type":"Comment","text":""},"encodingFormat":"text/html","suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/html","text":"complex curve. $1","comment":{"@type":"Comment","text":"complex curve. $1"}},{"@type":"Answer","position":1,"encodingFormat":"text/html","text":"curve convex to the Equator. $1","comment":{"@type":"Comment","text":"curve convex to the Equator. $1"}},{"@type":"Answer","position":2,"encodingFormat":"text/html","text":"straight line. $1","comment":{"@type":"Comment","text":"straight line. $1"}},{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"curve concave to the Equator. $1","comment":{"@type":"Comment","text":"curve concave to the Equator. $1"}}],"acceptedAnswer":[{"@type":"Answer","position":3,"encodingFormat":"text/html","text":"curve concave to the Equator. $1","comment":{"@type":"Comment","text":"On a Direct Mercator chart, apart from meridians and the Equator, a great circle will be represented by a curve concave to the Equator."},"answerExplanation":{"@type":"Comment","text":"On a Direct Mercator chart, apart from meridians and the Equator, a great circle will be represented by a curve concave to the Equator."}}]}]},{"@context":"https://schema.org/","@type":"AggregateRating","itemReviewed":{"@type":"Course","name":"US CPL (A) - Navigation General Navigation Practice Exam","description":"CPL (A) - Navigation General Navigation Practice Exam - Quiz: 709 questions with explanations and solutions, also available in PDF","provider":{"@type":"Organization","name":"Easy Quizzz","sameAs":"https://www.easy-quizzz.com"},"offers":[{"@type":"Offer","category":"CPL - Commercial Pilot Licence Test for Aeroplanes","priceCurrency":"USD","price":0}],"about":["Great Circles And Rhumb Lines","Basics of Navigation","Charts","Time","Visual Flight Rule (VFR) Navigation"],"hasCourseInstance":[{"@type":"CourseInstance","courseMode":"Online","courseWorkload":"PT20M"}]},"ratingCount":210,"ratingValue":4.6,"bestRating":5,"worstRating":0}]}
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Quiz
Question 1/101/10
Basics of Navigation
Basics of Navigation
Basics of Navigation
Given:
Planned true track:
283º
Planned true heading:
289º
Variation:
12ºE
Actual drift angle:
7ºR
Calculate the actual true track...
Select the answer:Select the answer
1 correct answer
A.
282º
$1
B.
296º
$1
C.
301º
$1
D.
284º
$1
To calculate the actual true track, you need to add the planned true track of 283º with the actual drift angle of 7ºR (right) as the drift is towards the right. Therefore, 283º + 7º = 290º. Then, adjust for the easterly variation of 12ºE by subtracting it from the result. So, 290º - 12º = 278º. However, since the variation is east, you need to add it instead. Therefore, 278º + 12º = 290º. Hence, the actual true track is 290º.
Right Answer: B
Quiz
Question 2/102/10
Time
Time
Time
On the 15th October, a pilot is departing from Auckland, New Zealand (37°00'S, 174°47'E,position west of the International Date Line; LT = UTC + 12 hours) for a flight to Honolulu inHawaii, U.S. (21°19'N, 157°55'W, position east of the International Date Line; LT = UTC - 10hours).When departing, the aircraft's master clock displays 08:15 UTC.After landing, the pilot records a flight time of 8 hours and 37 minutes.Which of the below statements is correct?
Select the answer:Select the answer
1 correct answer
A.
The aircraft arrives in Honolulu at 16:52 LT on the 15th October.
$1
B.
When the aircraft arrives in Honolulu, the local date in Auckland is still the 15th October.
$1
C.
Upon arrival the master clock of the aircraft displays 16:52 UTC and the local date is the 16th October.
$1
D.
The aircraft arrives in Honolulu at 06:52 LT on the 15th October.
$1
The aircraft arrives in Honolulu at 06:52 LT on the 15th October.
Right Answer: D
Quiz
Question 3/103/10
Visual Flight Rule (VFR) Navigation
Visual Flight Rule (VFR) Navigation
Visual Flight Rule (VFR) Navigation
(See Image). A pilot has planned a flight from aerodrome Strunkovice (LKSR) (N49°05', E014°04') to aerodrome Hohenfels (ETIH) (N49°13', E011°50') using the route shown on the annex. The pilot has been looking out while the aircraft has been drifting to the right of track. NOT looking at the stop watch, he/she mistakes EDNF (N48°50', E013°22') for EDMV (N48°38', E013°12') and turns right for the next leg. Seeing the mast, with elevation 3754 ft (N48°49', E013°13'), there are doubts about the aircraft's position. What is the best option to follow in order to re-establish the aircraft's position?
Select the answer:Select the answer
1 correct answer
A.
Continue on the present heading in order to reach the next waypoint
$1
B.
Circle to establish the aircraft's exact position.
$1
C.
Tune in the RODING (RDG) VOR/DME to confirm the aircraft's position and re-route accordingly.
$1
D.
Climb to a higher level, reverse track back to aerodrome Strunkovice, and re-route from there.
$1
.
Right Answer: C
Quiz
Question 4/104/10
Charts
Charts
Charts
Refer to the Annex or to chart E(LO)2 from the Jeppesen GSPRM 2017. Determine the initial track from position A (N54°53', W005°18') to position B (N55°18', W003°35') and also the distance from position A to the point of crossing the meridian of W004°00'.
Select the answer:Select the answer
1 correct answer
A.
Track: 070°(M); Distance: 48 NM
$1
B.
Track: 067°(T); Distance: 63 NM
$1
C.
Track: 064°(M); Distance: 48 NM
$1
D.
Track: 070°(T); Distance: 63 NM
$1
.
Right Answer: A
Quiz
Question 5/105/10
Great Circles And Rhumb Lines
Great Circles And Rhumb Lines
Great Circles And Rhumb Lines
Given the following information, calculate, to the nearest whole degree, the value of Earth convergence between positions A and B.A: 46°20'N, 005°40'WB: 62°40'N, 013°55'E.
Select the answer:Select the answer
1 correct answer
A.
24°
$1
B.
11°
$1
C.
16°
$1
D.
8°
$1
Earth convergence is the angle between two meridians at a specific latitude, caused by the Earth's curvature. To calculate it, we find the difference in longitude between the two positions (13°55'E - 5°40'W = 19°35'), then multiply this by the cosine of the mean latitude (54°30'N) to get the convergence of approximately 16°.
Right Answer: C
Quiz
Question 6/106/10
Basics of Navigation
Basics of Navigation
Basics of Navigation
The standard parallels of a Lambert’s conical projection are 07°40’N and 38°20’N. For this chart, what is the approximate constant of the cone?
Select the answer:Select the answer
1 correct answer
A.
0.60
$1
B.
0.39
$1
C.
0.42
$1
D.
0.92
$1
The constant of the cone for Lambert's conical projection can be calculated using the formula:
Constant = cos(standard parallel)1 + sin(standard parallel)1 * sin(standard parallel)2
Substituting the given standard parallels of 07°40’N and 38°20’N, the approximate constant of the cone is 0.39.
Right Answer: B
Quiz
Question 7/107/10
Time
Time
Time
While flying on an easterly track and crossing the dateline, the Local Time (LT) will (1)_____ and the date (2)_____.
Select the answer:Select the answer
1 correct answer
A.
(1) Move backward by 12 hours; (2) go back one day.
$1
B.
(1) Stay unchanged; (2) go back one day.
$1
C.
(1) Stay unchanged; (2) go forward by one day.
$1
D.
(1) Move forward by 12 hours; (2) go back one day.
$1
When flying on an easterly track and crossing the dateline, the Local Time (LT) will stay unchanged and the date will go back one day.
Right Answer: B
Quiz
Question 8/108/10
Visual Flight Rule (VFR) Navigation
Visual Flight Rule (VFR) Navigation
Visual Flight Rule (VFR) Navigation
On a topographical chart, contour lines that are very close together indicate that the terrain...
Select the answer:Select the answer
1 correct answer
A.
has a gradual slope.
$1
B.
is a level plain.
$1
C.
is a shallow mountain bowl.
$1
D.
is steep.
$1
Contour lines that are very close together on a topographical chart indicate that the terrain is steep.
Right Answer: D
Quiz
Question 9/109/10
Charts
Charts
Charts
Refer to chart E(LO)2_02 from Jeppesen GSPRM 2017.
Given the following bearing and range information obtained from DEN HELDER (HDR) VOR/DME (52°54´N, 004°46´E), what is the aircraft's position? (Note: Slant range corrections should be ignored)
Radial: 258°
Range: 63 NM
Select the answer:Select the answer
1 correct answer
A.
52°42´N, 003°04´E
$1
B.
52°46´N, 003°42´E
$1
C.
53°10´N, 003°03´E
$1
D.
52°46´N, 003°48´E
$1
.
Right Answer: A
Quiz
Question 10/1010/10
Great Circles And Rhumb Lines
Great Circles And Rhumb Lines
Great Circles And Rhumb Lines
On a Direct Mercator chart, apart from meridians and the Equator, a great circle will be represented by a…
Select the answer:Select the answer
1 correct answer
A.
complex curve.
$1
B.
curve convex to the Equator.
$1
C.
straight line.
$1
D.
curve concave to the Equator.
$1
On a Direct Mercator chart, apart from meridians and the Equator, a great circle will be represented by a curve concave to the Equator.
CPL (A) - Navigation General Navigation Practice Exam Practice test unlocks all online simulator questions
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Info quiz:
Quiz name:CPL (A) - Navigation General Navigation Practice Exam
Total number of questions:709
Number of questions for the test:100
Pass score:70%
Number of topics:5 Topics
Study topics:Number of questions:
Basics of Navigation:434 Questions
Charts:103 Questions
Great Circles And Rhumb Lines:63 Questions
Time:49 Questions
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